What is the value of tan(alpha+vita)
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tan (α + β) = sin(α+β)cos(α+β)sin(α+β)cos(α+β)
= sinαcosβ+cosαsinβcosαcosβ−sinαsinβsinαcosβ+cosαsinβcosαcosβ−sinαsinβ
= sinαcosβcosαcosβ+cosαsinβcosαcosβcosαcosβcosαcosβ−sinαsinβcosαcosβsinαcosβcosαcosβ+cosαsinβcosαcosβcosαcosβcosαcosβ−sinαsinβcosαcosβ, [dividing numerator and denominator by cos α cos β]
= tanα+tanβ1−tanαtanβtanα+tanβ1−tanαtanβ Proved
Therefore, tan (α + β) = tanα+tanβ1−tanαtanβ
= sinαcosβ+cosαsinβcosαcosβ−sinαsinβsinαcosβ+cosαsinβcosαcosβ−sinαsinβ
= sinαcosβcosαcosβ+cosαsinβcosαcosβcosαcosβcosαcosβ−sinαsinβcosαcosβsinαcosβcosαcosβ+cosαsinβcosαcosβcosαcosβcosαcosβ−sinαsinβcosαcosβ, [dividing numerator and denominator by cos α cos β]
= tanα+tanβ1−tanαtanβtanα+tanβ1−tanαtanβ Proved
Therefore, tan (α + β) = tanα+tanβ1−tanαtanβ
Abhishek9580:
plz explain
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hey !!!
here is ur answer :
Tan ( @+ bita ) = tan@+ tanbita / 1-tan@×tanbita .
hope it helps !!.
#Rajukumar111
here is ur answer :
Tan ( @+ bita ) = tan@+ tanbita / 1-tan@×tanbita .
hope it helps !!.
#Rajukumar111
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