what is the value of tan if sin is. 4/5
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Given ,
SinA = 4 / 5
then cosA = √ ( 1 - sin^2 A )
cosA = √ ( 1 - (4 / 5 ) ^2
cosA = √ ( 9 / 25 ) = 3 / 5
so now , TanA = sinA / cosA
TanA =( 4 / 5 ) / ( 3 / 5 )
tanA = 4 / 3
●hope it helps ●
SinA = 4 / 5
then cosA = √ ( 1 - sin^2 A )
cosA = √ ( 1 - (4 / 5 ) ^2
cosA = √ ( 9 / 25 ) = 3 / 5
so now , TanA = sinA / cosA
TanA =( 4 / 5 ) / ( 3 / 5 )
tanA = 4 / 3
●hope it helps ●
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