Question

What is the value of $6tan^{2} \Theta-\frac{6}{cos^{2} \Theta}$.

Answer 1

Answer:

The value of 6tan² θ − 6/cos² θ is - 6.

Step-by-step explanation:

Given : 6 tan² θ − 6/cos² θ

6 tan² θ − 6 × 1/cos² θ

= 6 tan² θ − 6 × sec² θ

[By using the identity, 1/ cosθ = secθ ]

= 6 (tan² θ −  sec² θ)

= - 6 ( sec² θ - tan² θ)

= - 6 × 1  

[By using  an identity, sec² θ -  tan² θ =  1]

6tan² θ − 6/cos² θ = - 6

Hence, the value of 6tan² θ − 6/cos² θ is - 6.

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Answer 2

Answer:

-6

Step-by-step explanation:

6 (tan θ)^2 - 6/(cos θ)^2

= 6[(sinθ)^2 - 1 ]

------------------------

(cos θ)^2

= -6