Question

What is the value of $\frac{(10^3)^{2} \times 10^{-4}} {10^{2}} ?$

Answer 1

$= \frac{10 {}^{6} \times 10 {}^{ - 4} }{10 {}^{2} }$
$= \frac{10 {}^{6 - 4} }{10 {}^{2} }$
$= \frac{10 {}^{2} }{10 {}^{2} }$
$= 1$