Question

What is the value of
$log_{9}(27) - log_{27}(9)$
​

Answer 1

Answer:

log9(27)−log27(9)

= log_{3 ^{2} }( {3}^{3} ) - log_{ {3}^{3} }( {3}^{2} )=log32(33)−log33(32)

= \frac{3}{2} \times log_{3}(3) - \frac{2}{3} \times log_{3}(3)=23×log3(3)−32×log3(3)

= \frac{3}{2} - \frac{2}{3}=23−32

= \frac{5}{6}=65

I HOPE IT WILL HELP YOU.