what is the value of
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Your Question :--- sin20*cosec20+cos20*sec20+tan20*cot20
we know that , by inverse ratios :-----
sin@ = 1/cosec@
cos@ = 1/sec@
tan@ = 1/cot@
from them , we get,
cosec20 = 1/sin20
sec20 = 1/cos20
tan20 = 1/cot20
putting values now we get,
sin20*1/sin20 + cos20*1/cos20 + tan20*1/tan20
=> 1 + 1 + 1
=> 3 (Ans) .
(Mark as brainlist)
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