Math, asked by Anonymous, 4 months ago

What is the value of
 \sin(theta)  {}^{2}  +  \cos(theta)  {}^{2}

Answers

Answered by Anonymous
8

Aɴsᴡᴇʀ ᴏғ ᴛʜɪs ǫᴜᴇsᴛɪᴏɴ :

sin²θ + cos²θ = 1

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Answered by Anonymous
16

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We know ,

  • Sin θ = opposite/hypothesis = O/H
  • cos θ = adjacent/hypothesis = A/H

\leadsto \sf \sin^{2}\theta +  \cos ^{2}\theta =   {\bigg( \dfrac{ O}{H} \bigg)}^{2}  + {\bigg( \dfrac{A}{H} \bigg)}^{2}

\leadsto \sf \sin^{2}\theta +  \cos^{2} \theta=   \dfrac{ {O}^{2} }{{H}^{2} }   + \dfrac{ {A}^{2} }{{H}^{2} }

 \leadsto\sf \sin^{2}\theta +  \cos^{2} \theta=   \dfrac{ {O}^{2} +  {A}^{2} }{{H}^{2} }

According to Pythagoras theorem.......

O² + A² = H²

\leadsto \sf \sin^{2}\theta  +  \cos ^{2}\theta=   \cancel \dfrac{{H}^{2}}{{H}^{2} }    = 1

hence, sin²θ + cos²θ = 1

________________

some more formula of trigonometry..

  1. sin²θ + cos²θ = 1
  2. sec²θ - tan²θ = 1
  3. cosec²θ - cot²θ = 1

☄ sin θ = O/H

☄ cosθ = A/H

☄ tan θ = O/A

☄ cot θ = A/O

☄ sec θ = H/A

☄ cosec θ = H/O

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