what is the value of
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Option (b) is correct : 3
Let x = [√6 + √6 + √6 + √6 + …..]
x = √(6 + x)...........(1)
On squaring both sides,
x² = 6 + x
x² - x - 6 = 0
x² - 3x + 2x - 6 = 0
[By middle term splitting]
x(x - 3) + 2(x - 3) = 0
(x - 3) (x + 2 ) = 0
(x - 3) = 0 (x + 2 ) = 0
x = 3 or x = - 2
On putting x = 3 in eq 1,
x = √(6 + x)
3 = √(6 +3)
3 = √9 = 3
This is possible
On putting x = - 2 in eq 1,
x = √(6 + x)
-2 = √(6 - 2)
- 2 = √4 = 2
This is not possible .
Hence , the value is 3 .
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