Question

what is the value of the below expression when A is equal to B? log(A2+B2)-logA-logB

Answer 1

Given,

Value of A = Value of B

To find,

Value of log(A²+B²)-logA-logB

Solution,

We can easily solve this mathematical problem by using the following mathematical process.

It is given that,

A = B

log A = log B (Taking log on both sides)

Given term :

= log (A²+B²)-logA-logB

= log (A²+A²)-logA-logA [Because, A = B and log A = log B]

= log (2A²) -2logA

= log 2 + log A² - 2 log A

= log 2 + 2 log A - 2 log A

= log 2

= 0.301 (approx)

Hence, the value of the given expression is log 2 or approximately 0.301