Question

What is the value of the current in a wire of 10 cm long at the right angle to the uniform magnetic field of 0.5 Weber/m2, when the force acting on the wire is 5 N

Answer 1

F =BIL cos(teta)

Therefore I = 5 /0.5 × 0.1 = 100 A

Answer 2

Concept:

If the magnetic induction is of the same strength and in the same direction throughout the region, the magnetic field is said to be uniform. In order to depict it, parallel lines are drawn.

Given:

The length of the wire is 10 cm and is placed at the right angle in a uniform magnetic field of 0.5 Wb/m². The force acting on the wire is 5 N.

Solution:

The length of the wire, L = 10 cm

The magnetic field, B = 0.5 Wb/m² and;

The force acting on the wire, F = 5 N

The angle at which the wire was placed in the magnetic field, θ = 90°

The force acting on the wire in a uniform magnetic field is given as:

$\overrightarrow{F}=i(\overrightarrow{l}\times \overrightarrow{B})$

F = iLB sin(θ)

5 = i(0.1)(0.5)(sin90°)

5 = 0.05(i)

i = 100 A

The value of the current in the wire is 100 A.

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