Question

What is the value of the discriminant, b2 − 4ac, for the quadratic equation 0 = x2 − 4x + 5, and what does it mean about the number of real solutions the equation has?

Answer 1

Answer:

can't understand this question sorry dude

Step-by-step explanation:

Answer 2

Answer:

discriminant is -4.

Step-by-step explanation:

If we write the equation in the form ax²+bx+c, then the equation becomes,

1x²+(-4)x+5.

Here, a = 1, b = -4, c = 5

b²-4ac = (-4)²-4×1×5 = 16-20 = -4

Here, the discriminant is negative, so this equation has 0 real solutions.