Question

What is the value of the discriminant for the quadratic equation 7r2−14r+10=0?

Answer 1

Answer:

-231

Step-by-step explanation:

a= 7 b = -14   c =10

discriminant = b^2 -4ac

                     =49 - 4[7][10]

                     = 49 -280

                     = -231

D < 0

THE ZEROS ARE IMAGINARY

Answer 2

$\mathfrak{\huge{\red{ANSWER}}}$

$<font color = "blue"><marquee>A = 7 B =14 C = 10</font color="blue"></marquee>$

b² - 4ac

= (14)² - 4×7×10

= 196 - 280

= -84