Question

what is the value of the expression (2t^2-t-28)divided(t-4)

Answer 1

x+7+4(x−5)=x+7+4x−20=x+4x+7−20

=5x−13

=5×2−13 [Putting x=2]

=10−13

=−3.

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Answer 2

Since,

$(2 {t}^{2} - t \: - 28) \\ \\ = 2( {t}^{2} - \frac{t}{2} - 14) \\ \\ = 2( {t}^{2} - 4t \: + \frac{7t}{2} \: - 14) \\ \\ = 2 \: ( \: t(t - 4) + \frac{7}{2} (t - 4)) \\ \\ = 2(t - 4)(t + \frac{7}{2} ) \\ \\ therefore \\ \\ \frac{(2 {t}^{2} - t - 28)}{ (t - 4)} \\ \\ = \frac{2(t - 4)(t + \frac{7}{2} )}{ (t - 4)} \\ \\ = 2(t + \frac{7}{2} )$