Math, asked by svetlana8239, 4 days ago

What is the value of the expression 4( x 2 +  xy) − 6 xy at  x = 2 and  y = −3?​

Answers

Answered by mdsaifsamads786
0

Answer:

Solution

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Correct option is C)

4xy(x−y)−6x

2

(y−y

2

)−3y

2

(2x

2

−x)+2xy(x−y)

=4x

2

y−4xy

2

−6x

2

y+6x

2

y

2

−6x

2

y

2

+3xy

2

+2x

2

y−2xy

2

=6x

2

y−6xy

2

−6x

2

y+3xy

2

=−3xy

2

=−3(5)(13)

2

=−2535

Step-by-step explanation:

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Answered by mahakulkarpooja615
0

Answer:

∴ The value of the expression 4(x^{2} +xy)-6xy at x=2 and y=-3 is 44.    

Step-by-step explanation:

In context to question asked,

  • We have to find the value of the expression 4(x^{2} +xy)-6xy at x=2 and y=-3.
  • To find the value of the expression, put x=2 and y=-3 in the given expression.
  • While solving the given expression, first solve the bracket, then addition and subtraction.
  • The given expression is,

    4(x^{2} +xy)-6xy = 4[(2)^{2} +2*(-3)]-6*2(-3)

                           = 4(8-6)+36

                           = 4*2+36

                           = 8+36

                           = 44

  • ∴ The value of the expression 4(x^{2} +xy)-6xy at x=2 and y=-3 is 44.    
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