Math, asked by lesy16, 5 months ago

What is the value of the expression x³yc^8/x²y²c^7 when x is 2, y is 3, and c is -2? a. -27/16 b. 27/16 c. 32/27 d. -32/27​

Answers

Answered by amitnrw
0

Given :  expression x³yc⁸/x²y²c⁷

To Find : value of the expression when x is 2, y is 3, and c is -2

Solution:

expression x³yc⁸/x²y²c⁷

xᵃ/xᵇ = xᵃ⁻ᵇ

aⁿ = 1/a⁻ⁿ   or a⁻ⁿ = 1/aⁿ

x³yc⁸/x²y²c⁷

= x³y¹c⁸/x²y²c⁷

= x³⁻².c⁸⁻⁷/y²⁻¹

= x¹.c¹/y¹

= xc/y

Substitute x = 2 , y = 3 and c = - 2

= 2(-2)/3

= - 4/3

None of the given option is correct

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