Question

What is the value of the lesser root of the equation x^2-3x+2=0 ?

Answer 1

Answer:

To find lesser root of the given equation which is

${x}^{2} - 3x + 2 = 0$

Firstly we have to calculate both roots of the equation and then we can compare both roots to find lesser one.

Now,

Roots of the equation can be calculated as,

${x}^{2} - 3x + 2 = 0 \\ {x}^{2} - 2 x- x + 2 = 0 \\ x(x - 2) - 1(x - 2) = 0 \\ (x - 2)(x - 1) = 0$

So,

Roots of given quadratic equation will be 2 and 1.

We know that 1<2.

So,

lesser route will be one.