Question

What is the value of the second derivative?​

Answer 1

answer :

$\sec( \frac{x + y}{x - y} ) = a {}^{2}$

defrentitate it with respect to x

$\sec( \frac{x + y}{x - y} ) \tan( \frac{x + y}{x - y} ) \times \frac{(x + y)(1 - \frac{dy}{dx}) - (x - y) (1 + \frac{dy}{dx}) }{(x - y) {}^{2} }$

simply the terms

and differentiable once more with respect to x

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Answer 2

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