What is the value of the shunt resistance that allows 20% of the main current through a galvanometer of 100 Ω ?
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Answer:
I'm sorry I don't know sorry
Answered by
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Answer:
25 ohm.
Explanation: igG=(i-ig)S
20/100×100=80/100S
20= 8/10S
200/8=S
S=25
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