Question

what is the value of the shunt resistance that allows the 40°/° of the main current through the galvanometer of 100​

Answer 1

Answer:

Correct option is

B

2Ω

Required shunt S=

(i−i

g

)

i

g

G

=

(i−

100

4

×i)

100

4

×i

=

25

24

i

25

i

×48

S=2Ω