What is the value of the sum of the first 100 even numbers?
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(2 + 4 + 6 +8 + … + 200)
= 2 × (1 + 2 + 3 + 4 + … 100)
= 2 × (1+100 + 2+99 + 3+98 + … + 50+51)
(Just changing the order of the numbers)
= 2 × (101 + 101 + 101 + … + 101)
This gives 50 pairs of numbers, each of which adds up to 101
= 2 × 50 × 101
= 10100
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