Math, asked by DAGGERBTW, 10 months ago

what is the value of this frac​

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Answers

Answered by tahseen619
2

\blue{\bf{\dfrac{\sqrt{3} + 1}{3}}}

Step-by-step explanation:

To Solve:

\dfrac{2 \sqrt{2}  +  \sqrt{6} }{3 \sqrt{2 +  \sqrt{3} } }

Solution:

\dfrac{2 \sqrt{2}  +  \sqrt{6} }{3 \sqrt{2 +  \sqrt{3} } }  \\  \\  \frac{2 \sqrt{2} + 2 \sqrt{2}. \sqrt{3}}{3 \sqrt{2 +  \sqrt{3}}}  \\  \\  \frac{  \sqrt{2}(2 +  \sqrt{3})}{3 \sqrt{2 +  \sqrt{3}}} \\  \\  \frac{ \sqrt{2}( \sqrt{2 +  \sqrt{3}})( \sqrt{2 +  \sqrt{3}}) }{3( (\sqrt{2 +  \sqrt{3}})} \\  \\   \frac{ \sqrt{2}( \sqrt{2 +  \sqrt{3}}) \cancel{( \sqrt{2 +  \sqrt{3}})} }{3\cancel{(\sqrt{2 +  \sqrt{3}}})} \\  \\  \frac{ \sqrt{2}(\sqrt{2 +  \sqrt{3} })}{3}  \\  \\  \frac{ \sqrt{2 \times 2 + 2 \times  \sqrt{3}}}{3} \\  \\   \frac{ \sqrt{4 + 2 \sqrt{3}}}{3} \\  \\  \frac{ \sqrt{3 + 1 + 2 \sqrt{3}}  }{3} \\  \\  \frac{  \sqrt{( \sqrt{3} + 1) {}^{2}  }  }{3}  \\  \\  \frac{ \sqrt{3}  + 1}{3}

Therefore, the required answer is \pink{\bf{\dfrac{\sqrt{3} + 1}{3}}}

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