Question

What is the value of van't hoff factor (i) if solute molecules undergo dimerisation?

Answer 1

The van't Hoff factor is 1/2.

Answer 2

Answer: Value of van't hoff factor for a solute undergoing dimerization is $\frac{1}{2}$.

Explanation:

If the solute undergo dimerization as:

                                       $2 A$  →  $A_{2}$

Initial moles                     $1$         $0$

Final moles                      $1-\alpha$     $\frac{\alpha }{2}$

Total number of moles at equilibrium = $1-\alpha + \frac{\alpha }{2}$

Assuming $\alpha = 100$%

Total number of moles at equilibrium = $1-1+\frac{1}{2 } = \frac{1}{2}$

Van't Hoff factor $i = \frac{1}{2}$

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