What is the value of vant hoffs factor for (NH4)2SO4
Answers
Answer:
We need to know the value of van't hoff factor.
The van't hoff factor is: 2.66 or 2.7 (approximately)
(NH₄)₂SO₄ is an ionic compound, so it dissociates in solution and produces 3 ionic species. Therefore van't hoff factor is more than one.
From the equation: ΔT_{b}Tb =i K_{b}Kb .m, where ΔT_{b}Tb = elevation of boiling point=102.5 - 100=2.5°C.
m=molality of solute=1.83 m (Given)
K_{b}Kb = Ebullioscopic constant or Boiling point elevation constant= 0.512°C/m (Given)
i= Van't Hoff factor
So, 2.5= i X 0.512 X 1.83
i=\frac{2.5}{0.512 X 1.83}0.512X1.832.5
i=2.66= 2.7 (approx.)
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Answer:
2.66 or 2.7
Explanation:
Value of vant hoffs factor for (NH4)2SO4 is 2.7.
NH4)2SO4-
1) Ammonium sulfate (American English and international scientific usage; ammonium sulphate in British English); (NH4)2SO4.
2) It is an inorganic salt with a number of commercial uses.
3)The most common use is as a soil fertilizer. It contains 21% nitrogen an d 24% sulfur.
FINAL ANSWER- 2.66 or 2.7
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