Question

what is the value of with proof

$\tan(11\pi \div 6)$
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Answer 1

Step-by-step explanation:

We have,

$\tan( \frac{11\pi}{6} )$

$= \tan(2\pi - \frac{\pi}{6} )$

We know that tan(2π - θ) = - tan(θ)

$= - \tan( \frac{\pi}{6} )$

$= - \frac{1}{ \sqrt{3} }$