what is the value of (x-√2)(x-√2)
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According to the question, we need to find ⭕(x-√2)²= x² + (√2)² - 2×x×√2 = x² + 2 - 2√2
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Hey mate ur Answer is here⤵
(x- root 2 )( x -root 2)
=( x - root 2)^2
= x^2 - 2.x . root 2 + root 2 ^2
= x^2 - 2root2x + 2
= x^2 - 2root2x -2root2x + 2 =0
= x( x - 2root2 ) - 2root2 ( x - 2root2 ) =0
= (x - 2root2 )( x - 2root2 ) = 0
= x = 2root2 Ans.
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