Math, asked by laxmikantrunthala, 11 months ago

what is the value of (x-√2)(x-√2)​

Answers

Answered by sunil4748
2

According to the question, we need to find ⭕(x-√2)²= x² + (√2)² - 2×x×√2 = x² + 2 - 2√2

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Answered by naina5816
0

Answer:

Hey mate ur Answer is here⤵

(x- root 2 )( x -root 2)

=( x - root 2)^2

= x^2 - 2.x . root 2 + root 2 ^2

= x^2 - 2root2x + 2

= x^2 - 2root2x -2root2x + 2 =0

= x( x - 2root2 ) - 2root2 ( x - 2root2 ) =0

= (x - 2root2 )( x - 2root2 ) = 0

= x = 2root2 Ans.

I HOPE IT HELPS U ✌ ✌ ✌ ✌

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