What is the value of,. (x^3)+(1/x^3)-2
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a³+b³+c³ -3.a.b.c = (a+b+c)(a²+b²+c²-a.b-bc-ca) . . . . . . . . .(1)
x³ + 1/x³ - 2
=> x³ + 1/x³ + 1 - 3
=> (x)³ + (1/x)³ + (1)³ – 3.x.1/x.1
=> (x + 1/x + 1)(x² + 1/x² + 1²- x.1/x-1/x.1–1.x)
=> (x+1/x+1)(x² + 1/x² + 1 – 1 – 1/x - x)
=> (x+1/x+1)(x² + 1/x² – 1/x - x)
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