Math, asked by bryanblood, 1 year ago

What is the value of x?

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Answered by MarkAsBrainliest
0
\bold{Answer :}

Here, RSQ is a right-angled triangle whose base is RQ = z units (say), height is SR = x units and hypotenuse is SQ = (9 + 16) = 25 units

By Pythagoras theorem,

SR² + RQ² = SQ²

x² + z² = 25²

or, z² = 25² - x²

or, z = √(625 - x²)

So, RQ² = (625 - x²) units

Let us take RT = w units

Applying Pythagoras theorem on RTQ triangle, we get

RT² + TQ² = RQ²

or, w² + 16² = 625 - x²

or, w² = 625 - 256 - x²

or, w² = 369 - x²

So, RT² = 369 - x²

Again, applying Pythagoras theorem on RST triangle, we get

RT² + ST² = RS²

or, 369 - x² + 9² = x²

or, 2x² = 369 + 81

or, 2x² = 450

or, x² = 225

or, x = 15, since length is always positive

Therefore, the value of x is 15 units.

#\bold{MarkAsBrainliest}
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