What is the value of x^6 if (x+1/x)² = 3?
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Answer:
( x + 1 / x ) ²
Use identity
( a / b ) ² = a² / b²
( x + 1 ) ² = x² / 1²
========> x² / 1 = ( x )6
========> 1 = x6 × x²
Use identity
( a ) m × ( a ) n = ( a ) m + n
=====> 1 = ( x ) 6 + 2
====> 1 = ( x ) 8
====> ( x ) 8 = 1
====> x^8 - ( 1 ) = 0
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