Question

What is the value of x and y if 2x-3y=4 and 3y-8x-2=0?

Answer 1

$\textbf{Answer :}$

The given equations are

2x - 3y = 4 ...(i)

and 3y - 8x - 2 = 0 ...(ii)

Now, adding (i) and (ii), we get

2x - 3y + 3y - 8x - 2 = 4

⇒ - 6x = 4 + 2

⇒ 6x = - 6

⇒ x = - 1

Putting x = - 1 in (i), we get

2 (- 1) - 3y = 4

⇒ - 2 - 3y = 4

⇒ 3y = - 2 - 4

⇒ 3y = - 6

⇒ y = - 2

∴ the required solution be

x = - 1 and y = - 2

#$\textbf{MarkAsBrainliest}$

Answer 2

2x-3y=4 -(1)

3y-8x=2

= -8x+3y=2

-(8x-3y)=2

8x-3y=-2 -(2)

Substracting (1) from (2)

8x-3y-(2x-3y)=-2-4

8x-3y-2x+3y=-6

8x-2x=-6

6x=-6

X=-1

Than

2x-3y=4

2(-1)-3y=4

-2-3y=4

-3y=4+2

-3y=6

y=-2

Hence X=-1 and y=-2