Question

What is the value of x and y if x²+y²-2x+4y=-5​

Answer 1

Answer:

Given equation is x

2

+y

2

−2x+4y−5=0

On differentiating, we get

2x+2y

dx

dy

−2+4

dx

dy

=0

⇒(y+2)

dx

dy

=1−x

⇒(

dx

dy

)

(2,1)

=

1+2

1−2

=

3

−1

⇒−(

dy

dx

)

(2,1)

=3

Now, equation of normal is

(y−1)=3(x−2)

y−1=3x−6

⇒y=3x−5