What is the value of x and y if x²+y²-4x-3y-1=0 ?
Answers
Step-by-step explanation:
Amitnrw★ Brainly Teacher ★
k = - 3 if the radius of circle x² + y² - 2x + 3y + k =0 is 5/2
2x - 2y = 5 is equation of diameter of the circle which passes through the point (5,5/2)
Step-by-step explanation:
x² + y² - 2x + 3y + k =0
=> (x - 1)² - 1 + ( y + (3/2))² - 9/4 + k = 0
=> (x - 1)² + (y + 3/2)² = 13/4 - k
Center of Circle = 1 , - 3/2
radius = √(13/4 - k)
=> 13/4 - k = (5/2)²
=> 13/4 - k = 25/4
=> k = - 3
Diameter will Pass through center & also passing throough (5 , 5/2)
slope = (5/2 -(-3/2))/(5 -1)
= 4/4
= 1
y = x + c
5/2 = 5 + c
=> c = -5/2
=> y = x - 5/2
=> 2y = 2x - 5
=> 2x - 2y = 5
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