Question

What is the value of x and y when, 39x52 + 278y = y2y3x?​

Answer 1

Answer:

x = 6 and y = 4

Step-by-step explanation:

Since we want to know what is the value of x and y when, 39x52 + 278y = y2y3x.

In the equation that is given to us, the first digit of each number is 2 then y and x.

Hence, x = y+2

Thus, the sum of the second digits is 5+8= 13 which gives us the information that 1 is carry forwarded to next digit.

x + 7 + 1 = 10 + y and 1 is carried once more.

Then:

9 + 2 + 1 = 12 and 1 is carried once more.

Now last digit is 3 and only carry forwarded term 1, thus:

3 + 1 = y

⇒ Y = 4

Since x = y+2, we have:

x = 4 + 2

⇒ x = 6

Hence, our solution is x = 6 and y = 4.