Question

What is the value of x , angleP, angleQ and angleR​

Answer 1

Answer:

∠p = 76° ; ∠q = 37° ; ∠r = 72°

Step-by-step explanation:

here , we have to find ∠p,∠q,∠r from the given figure

acc to the qn ,

∠p=2x+2

∠q= x

∠r = 2x-7

acc to angle sum property,

∠p + ∠q + ∠r = 180

2x+2+x+2x-7 = 180

5x - 5 = 180

5x = 185

x = 185/5 = 37

therefore,

∠p=2x+2 = 2x37 + 2 = 76°

∠q= x = 37°

∠r = 2x-7  2 x 37 - 2 = 72°

hope it helps

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Answer 2

Answer:

here ,

angle P = 2x + 2

angle Q = x

angle R = 2x-7

since we know total angle of a triangle is 180⁰

so ,

angle P + angle Q + angle R = 180⁰

(2x + 2) + x + (2x -7) = 180⁰

2x + 2+ x + 2x -7 = 180⁰

2x +x + 2x = 180 + 7 - 2

5x = 185

x = 185/5

x = 37⁰

Therefore , x = 37

so ,

angle P = (2x + 2 )

= 2× 37 + 2 = 76⁰

angle Q = x = 37⁰

angle R = ( 2x -7)

= 2×37 - 7 = 67⁰

( if you calculate ,the total angle is 180⁰)