What is the value of x?
[Art not to scale.]
x = 23
x = 35
x = 58
x = 93
Answers
In given ΔSQR,
∠S = 35°, ∠R = 58° and ∠Q = ?
We have to find, the value of x°.
Solution:
We know that:
The sim of three angles of triangle = 180°
∴ ∠S + ∠R + ∠Q = 180°
⇒ 35° + 58° + ∠Q = 180°
⇒ 93° + ∠Q = 180°
⇒ ∠Q = 180° - 93°
⇒ ∠Q = 87°
According to given figure:
∠Q + x° = 180°
⇒ 87° + x° = 180°
⇒ x° = 180° - 87°
⇒ x° = 93°
⇒ x = 93
Thus, the required "option is d)".
Given : A triangle SQR
∠S = 35°
∠R = 58°
External ∠Q = ∠SQP = x°
To Find : Value of x
x = 23
x = 35
x = 58
x = 93
Solution:
Method 1 :
Using Directly Exterior angle of triangle = Sum of opposite two internal angles
=> ∠SQP = ∠S + ∠R
=> x° = 35° + 58°
=> x° = 93°
Hence value of x = 93
Method 2 :
Using Sum of angles of triangle and Linear Pair
Sum of angles of triangle = 180°
=> ∠Q + ∠S + ∠R = 180°
=> ∠Q + 35° + 58° = 180°
=> ∠Q = 87°
∠SQP + ∠Q = 180° Linear Pair
=> x° + 87° = 180°
=> x° = 93°
Hence value of x = 93
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