Question

what is the value of x at a point on the curve y = x2 - 8x + 3 where the slope is 2.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Concept:

The slope of a curve at one point equals the slope of a tangent line to the curve. We take the following actions to calculate the slope, First, we must separate the supplied equation, or more simply, we must determine the dy/dx of an equation. We shall obtain the slope equation after differentiating. In order to calculate the slope, put the value of x into the equation.

Given:

Curve "y = x² - 8x + 3" where the slope is 2.

Find:

We have to find the value of "x".

Solution:

                            y=x² −8x+3

For the slope of tangent differentiate with respect to 'x'

                              dx/dy =2x−8

Slope of tangent = 2 ( given)

                    2x−8=2

                       x−4=1

                           x= 5

Hence, the value of "x" is 5.

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