Math, asked by mdazad325223, 9 months ago

what is the value of x+b/a-b=x-b/a+b​

Answers

Answered by Shailesh183816
1

\bf\large\underline\blue{Solution:-}

Given x+b/a-b = x-b/a+b can be written as

           (x+b)(a+b) = (x-b)(a-b)

          xa + xb + ab + b^2 = xa - bx - ba + b^2

          xa + xb + ab + b^2 - xa + bx + ba - b^2

          2xb + 2ab = 0

           2b(x + a) = 0

           x + a = 0

          x = -a.

Answered by Anonymous
2

Answer:

Given x+b/a-b = x-b/a+b can be written as

(x+b)(a+b) = (x-b)(a-b)

xa + xb + ab + b^2 = xa - bx - ba + b^2

xa + xb + ab + b^2 - xa + bx + ba - b^2

2xb + 2ab = 0

2b(x + a) = 0

x + a = 0

x = -a.

Similar questions