what is the value of x for which 3 is a root of the equation Kx^2-7x+3=0
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Answer:
- K = 1
Step-by-step explanation:
- step 1:
put the value of x+3
therefore, k(3)^2 - 7(3) +3=0
- step 2:
multiply them
then ,we will get
k9 - 21 + 3=0
- step 3:
add 3 to -21
then we will get
k9 - 9 =0
- step 4:
take -9 to the LHS
then,
k9 = 0 - 9
k9 =9
- step 5:
take the next 9 to the LHS
therfore,
k = 9/9
then K = 1
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