what is the value of 'x' if 0.14x (x) + 0.14x - 0.14 = 0 ?
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Answered by
7
Hiii...
0.14(X^2+X-1)=0
X^2+X-1 =0
formulae= -b + or - square foot of b^2 -4ac /2a
so,
-1 + or- square root of 1^2-4×1×-1/2×1
-1 + or - square root of 1+4/2
-1 + or - square root of 5/2
so ans is (-1 + square root of 5/2)(-1- square root of 5/2)
0.14(X^2+X-1)=0
X^2+X-1 =0
formulae= -b + or - square foot of b^2 -4ac /2a
so,
-1 + or- square root of 1^2-4×1×-1/2×1
-1 + or - square root of 1+4/2
-1 + or - square root of 5/2
so ans is (-1 + square root of 5/2)(-1- square root of 5/2)
divyareddy7440:
yup I am a telugite
hmmm
hlo divya
Hii
hey divya ..thanks But i did a blander mistake in question. . srryyy .. !!
actually the question was this : 4x(x) + 0.14x - 0.14 = 0 , now whts the vakue of x ? .. this was the question.
Hii
it's ok no probs dude
Answered by
2
5/2 is the answer hope you the formula
thanksss ..
. but i m stupid ..i did a mistake in question
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