Question

what is the value of x ,if 16x =(62)^2 -(26)^2

Answer 1

The answer is given below :

Given that,

16x = 62² - 26² .....(i)

By identity, we know that,

a² - b² = (a + b)(a - b)

Using it in RHS of (i), we get

16x = (62 + 26)(62 - 26)

=> 16x = 88 × 36

=> 4 × 4 × x = 4 × 22 × 4 × 9

=> x = 22 × 9, removing (4 × 4) from both sides

=> x = 198

Therefore, the required solution is 198.

Thank you for your question.

Answer 2

hope it helps

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