Question

What is the value of x if mean of x,x+2, x+4,x+6 and x+8 is 11?

Answer 1

Answer:

(x + x+2 + x+4 + x+6 + x+8)÷5 = 11

Step-by-step explanation:

5x + 20 = 11×5

5x= 55 - 20

x= 35÷ 5

= 7

Answer 2

Step-by-step explanation:

{ Mean =

$\frac{sum \: o f \: observations}{no. \: of \: observations}$

11=x+x+2+x+4+x+6+x+8/5

(replacing in like terms)

11=x+x+x+x+x+2+4+6+8/5

11=5x+20/5

=>5x=20-11/5

5x=9/5

=>x=9/5÷5/1

x=9/5*1/5

x=9/25

Therefore, the value of 'x' = 9/25

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