What is the value of x if |x +1| + √(x-1) = 0 ?
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Answer:
We have,
x−
x
1
=(
2
)i ……… (1)
On squaring both sides, we get
(x−
x
1
)=((
2
)i)
2
x
2
+
x
2
1
−2=2i
2
x
2
+
x
2
1
−2=−2
x
2
+
x
2
1
=0
x
4
+1=0
x
4
=−1 ……… (2)
Since,
x
2187
−
x
2187
1
=x
3
(x
4
)
546
−
x
3
(x
4
)
546
1
From equation (2),
x
2187
−
x
2187
1
=x
3
×1−
x
3
×1
1
x
2187
−
x
2187
1
=x
3
−
x
3
1
Since, a
3
−b
3
=(a−b)(a
2
+b
2
+ab)
Therefore,
x
2187
−
x
2187
1
=(x−
x
1
)(x
2
+
x
2
1
+1)
x
2187
−
x
2187
1
=(
2
)i(0+1)
x
2187
−
x
2187
1
=(
2
)i
Hence, this is the answer.
Step-by-step explanation:
to get a clear explanation I have attached image
Attachments:
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