what is the value of x in given circle.
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the angle substended in the centre is twice the angle substented by it in any part of the remaining circle,therefore,
angle AOB =2 times of angle ACB
angle AOC =2×40°
angle AOC =80°
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Theorem angles subtended to the center is twice the angle subtended by the same arc to the circle
in the given figure
arc AB subtend an angle AOB to the center and also angle ACB to the circle
so by the given theorem
AOB=2 x ACB
X =2x 40 degree
so X=80 degrees
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