Question

what is the value of x in log1728bas2 root 3​

Answer 1

Answer:x=6

Step-by-step explanation:

log1728 to the base 2$\sqrt{3\\}$ = log1728to the base$\sqrt{12}$

Therefore sqrt12 raised to 6 is 1728..

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Answer 2

Answer:

$if \: \: log_{2 \sqrt{3} }(1728) = x \: \: then \: \: \\ {2 \sqrt{3} }^{x} = 1728 \\ or \: \: {2 \sqrt{3} }^{x } \: = {2 \sqrt{3} }^{6} \\ so \: \: we \: can \: write \: x = 6$

So the answer will be 6

Step-by-step explanation:

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