Question

what is the value of x in log2(x-3)+log2(x+3)=4 if u tell the ans i will mark as brainly​

Answer 1

Answer:

log A + log is equals to log a b by which you can solve the question

Answer 2

We have a product sum of log functions. We can rewrite this as a product of the logs.

Log2[(x - 3)(x + 2)] = -4

Log2(x2 - x - 6) = -4

Since -4 is the solution of the Log, it will be the exponent of the 2.

2-4 = x2 - x - 6

1/16 = x2 - x - 6

Multiply both sides of equation by 16 to get rid of the denominator.

1 = 16x2 - 16x - 96

Subtract 1 on both sides of equation.

0 = 16x2 - 16x - 97

Use the quadratic formula:

x = (16 ± √(162 - 4(-1552))) / 32

x = (16 ± √(256 + 6208)) / 32

x = (16 ± 80.40) / 32

x1 = 3.01

x2 = -2.01