What is the value of x in the equation 4x + 8y = 40, when y = 0.8
Answers
Answered by
12
4x+8y=40
y=0.8
4x+8(0.8)=40
4x+6.4=40
4x=40-6.4
4x=33.6
x=33.6/4
x=8.4
y=0.8
4x+8(0.8)=40
4x+6.4=40
4x=40-6.4
4x=33.6
x=33.6/4
x=8.4
Answered by
2
Given :
- y = 0.8
- Equation : 4x + 8y = 40
To find :
The value of x
Solution :
Substituting value of y = 0.8 in above given equation
4x + 8×(0.8) = 40
4x + 6.4 = 40
4x = 40 - 6.4
4x = 33.6
x = 33.6 / 4
x = 8.4
• Hence, value of x for which y is equal to 0.8 is 8.4
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