Question

what is the value of x in the expression {(sqrt(3025)+sqrt(0.0678-x)}=55.26
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Answer 1

SOLUTION :

TO DETERMINE

The value of x in the expression

$\sf{} \sqrt{3025} + \sqrt{0.0678 - x} = 55.26$

EVALUATION

$\sf{} \sqrt{3025} + \sqrt{0.0678 - x} = 55.26$

$\implies \sf{} 55 + \sqrt{0.0678 - x} = 55.26$

$\implies \sf{} \sqrt{0.0678 - x} = 55.26 - 55$

$\implies \sf{} \sqrt{0.0678 - x} = 0.26$

Squaring both sides we get

$\implies \sf{} {0.0678 - x} = 0.0676$

$\implies \sf{} x = 0.0678 - 0.0676$

$\implies \sf{} x = 0.0002$

CHECK STEP

Here

$\sf{} \sqrt{3025} + \sqrt{0.0678 - x} = 55.26 \: \: \: ....(1)$

Putting x = 0.0002 in LHS of (1) we get

LHS

$\sf{} \sqrt{3025} + \sqrt{0.0678 - 0.0002}$

$\sf{} = \sqrt{3025} + \sqrt{0.0676}$

$= \sf{} 55 + 0.26$

$\sf{} = 55.26$

= RHS

Hence Verified

FINAL RESULT

The value of x in the expression

$\sf{} \sqrt{3025} + \sqrt{0.0678 - x} = 55.26 \: \: is \: \: \: 0.0002$

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