Question

What is the value of x in the given figures? ​

Answer 1

Answer:

In the figure A, ∠A$=70$°,  in figure B, ∠$B=$∠$C=$ $62$°.

Step-by-step explanation:

In figure A, ∠ACD  and ∠ACB  are angles on a straight line, their sum is $180$°.

Therefore, ∠ACD$=$$180-$∠ACB

                            $=180-40=140$°

that is $2x=140$°

implies  $x=70$°.

In figure B,

since opposite angles are equal, ∠$BAC=56$°.

and total of three angles in a triangle is $180$°, therefore

in Δ$ABC$,

$x+x+56=180\\2x+56=180\\2x=180-56=124\\\\x=62$.

hence the answer

thank you