What is the value of x in2x2– 7x + 3 = 0?
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We have,
2x^2 - 7x + 3
= 2x^2 -6x -x +3
= 2x(x + 3) -( x -3 ) =0
= (2x -1 )( x -3 )= 0
therefore, the first root of the equation is
2x - 1 = 0
x =1 /2
and second root is
x -3 =0
x = 3
2x^2 - 7x + 3
= 2x^2 -6x -x +3
= 2x(x + 3) -( x -3 ) =0
= (2x -1 )( x -3 )= 0
therefore, the first root of the equation is
2x - 1 = 0
x =1 /2
and second root is
x -3 =0
x = 3
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