Question

what is the value of x.
please​

Answer 1

Answer:

x=3 and x=4

Step-by-step explanation:

first shift x-3 to RHS

and you get

x²-7x+12=0

then solve it either by splitting the middle term or applying quadratic formula

x²-7x+12=0

x²-4x-3x+12=0

x(x-4)-3(x-4)=0

(x-4)(x-3)=0

the value of x is 3 or 4

Answer 2

Answer:

x=4

Step-by-step explanation:

$\frac{x^{2} -7x + 12}{x-3} \\\frac{x^{2} -4x-3x+12}{x-3}\\ \frac{x(x -4)-3(x-4)}{x-3} \\\frac{(x-3)(x-4)}{x-3}\\x-4\\\\\\x-4=0\\x=4$