what is the value of x? solve x²-4-[x]=0
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x^2 - x - 4 = 0
x = [-b ±√(b^2 - 4ac)]/2a
a = 1
b = -1
c = -4
x = [1 ±√(1 + 16)]/2
x = [1 ±√17]/2
x = [1 ±4.12]/2 (approx.)
x = [1 + 4.12]/2
x = 5.12/2
x = 2.56
x = [1 - 4.12]/2
x = -3.12/2
x = -1.56
∴ x = -1.56 , 2.56
x = [-b ±√(b^2 - 4ac)]/2a
a = 1
b = -1
c = -4
x = [1 ±√(1 + 16)]/2
x = [1 ±√17]/2
x = [1 ±4.12]/2 (approx.)
x = [1 + 4.12]/2
x = 5.12/2
x = 2.56
x = [1 - 4.12]/2
x = -3.12/2
x = -1.56
∴ x = -1.56 , 2.56
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